Answer
$(x+1)^2+(y-3)^2=1$
Work Step by Step
Based on the given conditions, the radius is the distance from the center to $y=2$, thus $r=3-2=1$, we have $(x+1)^2+(y-3)^2=1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter F - Foundations: A Prelude to Functions - Section F.4 Circles - F.4 Assess Your Understanding - Page 38: 41
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