Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.4 Circles - F.4 Assess Your Understanding - Page 38: 29

Answer

(a). $(h,k)=(\frac{1}{2},-1), r=\frac{1}{2}$. (b). See graph. (c). $(0,-1)$.

Work Step by Step

(a). $x^2+y^2-x+2y+1=0 \longrightarrow (x-\frac{1}{2})^2+(y+1)^2=\frac{1}{4}$, thus $(h,k)=(\frac{1}{2},-1), r=\frac{1}{2}$. (b). See graph. (c). For x-intercept(s), let $y=0$, we get $none$, for y-intercept(s), let $x=0$, we get $(0,-1)$.
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