Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.4 Circles - F.4 Assess Your Understanding - Page 38: 18

Answer

$(x+5)^2+(y+2)^2=49$, $ x^2+y^2+10x+4y-20=0$, See graph.

Work Step by Step

Step 1. Based on the given data, we can write the standard form as $(x+5)^2+(y+2)^2=49$, Step 2. The general form is $x^2+y^2+10x+4y+25+4-49=0\longrightarrow x^2+y^2+10x+4y-20=0$, Step 3. See graph.
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