Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.4 Circles - F.4 Assess Your Understanding - Page 38: 2



Work Step by Step

Apply square root property by taking the square root of both sides: $\sqrt{(x-2)^2}=\pm \sqrt{9}\\ x-2= \pm 3\\ x=2\pm 3$ Thus, $x_1=2+3=5\\ x_2=2-3=-1$
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