Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.1 The Distance and Midpoint Formulas - F.1 Assess Your Understanding - Page 7: 51


$(\frac{s}{2},\frac{s}{2})$ and $(\frac{s}{2},\frac{s}{2})$

Work Step by Step

Step 1. Use the given Hint, we have on diagonal as from $(0,0)$ to $(s,s)$, and we can find its midpoint as $(\frac{s}{2},\frac{s}{2})$. Step 2. The other diagonal is from $(0,s)$ to $(s,0)$, and we can find its midpoint as $(\frac{s}{2},\frac{s}{2})$ which is the same as in Step 1. Step 3. Thus, we can draw the conclusion that the diagonals of a square intersect at their midpoints.
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