Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.1 The Distance and Midpoint Formulas - F.1 Assess Your Understanding - Page 7: 25



Work Step by Step

Let $(x_{1},y_{1})=(-0.2, 0.3)$ $(x_{2},y_{2})=(2.3, 1.1)$ Now, $d=\sqrt {(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ Substitute the given values into the formula above to obtain: $d= \sqrt {(2.3+0.2)^{2}+(1.1-0.3)^{2}}$ $d=\sqrt {(2.5)^{2}+(0.8)^{2}}$ $d=\sqrt {6.25+0.64}$ $d=\sqrt {6.89}$ $d\approx2.62$
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