## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$d=\sqrt{68}=2\sqrt{17}$
To calculate the distance $d$ between two points, we have: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ Plug the $x$ and $y$ coordinates of the given points to obtain: $d=\sqrt{(5-3)^2+(4-(-4))^2}=\sqrt {4+64}=\sqrt{68}$ If we further simplify, then $d=\sqrt{68}=\sqrt{4(17)} = 2\sqrt{17}$