Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.1 The Distance and Midpoint Formulas - F.1 Assess Your Understanding - Page 7: 24

Answer

$5\sqrt 5$ units

Work Step by Step

To calculate the distance $d$ between two points, we have: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ Substitute the $x$ and $y$-coordinates of the given points to obtain: $d=\sqrt{[6-(-4)]^2+[2-(-3)]^2}\\ d=\sqrt{10^2+5^2}\\ d=\sqrt {100+25}\\ d=\sqrt{125}\\ d=\sqrt{(25)(5)}\\ d=5\sqrt 5$
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