Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.1 Polar Cordinates - 8.1 Assess Your Understanding - Page 592: 72


$2r^3sin(2\theta) cos\theta-1=0$

Work Step by Step

Use the relations $x=r\ cos\theta$ and $y=r\ sin\theta$, we have: $4x^2y=1$, $4(r\ cos\theta)^2(r\ sin\theta)=1$, $4r^3sin\theta cos^2\theta=1$, $2r^3sin(2\theta) cos\theta-1=0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.