Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.1 Polar Cordinates - 8.1 Assess Your Understanding - Page 592: 55

Answer

$(3, 0)$

Work Step by Step

The conversion of rectangular coordinates $(x,y)$ to polar coordinates $(r, \phi)$ can be computed as: $r=\sqrt{x^2+x^2}$ and $\theta=\tan^{-1}(\dfrac{y}{x})$ We have: $r=\sqrt{3^2+0^2}=3$ and $\theta=\tan^{-1}\left(\dfrac{0}{3}\right)=0$ Therefore, the point $(x,y)$ has coordinates $(3, 0)$ in the rectangular coordinate system.
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