Answer
$(2.31, 3.05)$
Work Step by Step
Solve for $r$ using the formula $r=\sqrt {x^{2}+y^{2}}$ to obtain:
$$r=\sqrt {(-2.3)^{2}+(0.2)^{2}}\approx2.31$$
Solve for the reference angle using the formula $\alpha=\tan^{-1}(\frac{y}{x})$ to obtain:
$$\alpha=\tan^{-1}\left(\frac{0.2}{-2.3}\right)\approx-0.0867$$
Since $(-2.3, 0.2)$ is in the second quadrant, then
$$\theta=\alpha+\pi=-0.0867+3.14=3.05$$
Thus, the polar coordinates for the point $(-2.3, 0.2)$ is $(2.31, 3.05)$.
