Answer
$(2, \dfrac{\pi}{2} )$
Work Step by Step
The conversion of rectangular coordinates $(x,y)$ to polar coordinates $(r, \phi)$ can be computed as:
$r=\sqrt{x^2+x^2}$ and $\theta=\tan^{-1}(\dfrac{y}{x})$
We have: $r=\sqrt{0^2+2^2}=\sqrt 4=2$
and $\theta=\tan^{-1}\left(\dfrac{2}{0}\right)=\dfrac{\pi}{2}$
Therefore, the point $(x,y)$ has coordinates $(2, \dfrac{\pi}{2} )$ in the polar coordinate system.