Answer
$(\frac{\pi}{4},1)$, $(\frac{5\pi}{4},1)$, $(\frac{9\pi}{4},1)$, $(\frac{13\pi}{4},1)$.
Work Step by Step
1. To find the intersects, let $tan(x)=1$, in a unit circle, this corresponds to angle $x=\frac{\pi}{4}$ and $x=\frac{5\pi}{4}$.
2. The period of the function is $\pi$, thus we can find four intersects $(\frac{\pi}{4},1)$, $(\frac{5\pi}{4},1)$, $(\frac{9\pi}{4},1)$, $(\frac{13\pi}{4},1)$.
