Answer
$(\frac{3\pi}{2},-2)$, $(\frac{7\pi}{2},-2)$, $(\frac{11\pi}{2},-2)$, $(\frac{15\pi}{2},-2)$.
Work Step by Step
1. To find the intersects, let $2sin(x)=-2$ to get $sin(x)=-1$, in a unit circle, this corresponds to angle $x=\frac{3\pi}{2}$.
2. The period of the function is $2\pi$, thus we can find four intersects $(\frac{3\pi}{2},-2)$, $(\frac{7\pi}{2},-2)$, $(\frac{11\pi}{2},-2)$, $(\frac{15\pi}{2},-2)$.
