Answer
$2x+h-5$
Work Step by Step
1. Given $f(x)=x^2-5x+1$, we have $f(x+h)=(x+h)^2-5(x+h)+1$
2. We have $f(x+h)-f(x)=(x+h)^2-5(x+h)+1-(x^2-5x+1)=2xh+h^2-5h$
3. Thus $\frac{f(x+h)-f(x)}{h}=2x+h-5$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.4 Graphs of the Sine and Cosine Functions* - 5.4 Assess Your Understanding - Page 435: 105
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