Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.4 Graphs of the Sine and Cosine Functions* - 5.4 Assess Your Understanding - Page 435: 106

Answer

$(2,5)$.

Work Step by Step

$g(x)=-3x^2+12x-7=-3(x^2-4x+4)+5=-3(x-2)^2+5$, thus the vertex is at $(2,5)$.
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