Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.6 Logarithmic and Exponential Equations - 4.6 Assess Your Understanding - Page 338: 92

Answer

$ln(3\pm2\sqrt 2)\approx \pm1.763$

Work Step by Step

1. $\frac{e^x+e^{-x}}{2}=3 \Longrightarrow 2e^x(\frac{e^x+e^{-x}}{2})=6e^x \Longrightarrow e^{2x}-6e^x+1=0 \Longrightarrow e^x=\frac{6\pm\sqrt {36-4}}{2}=3\pm2\sqrt 2 \Longrightarrow x=ln(3\pm2\sqrt 2)\approx \pm1.763$ 2. Check, $x=ln(3\pm2\sqrt 2)$ fit(s).
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