Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.6 Logarithmic and Exponential Equations - 4.6 Assess Your Understanding - Page 338: 85

Answer

$\frac{26\pm 8\sqrt {10}}{9}\approx0.078,5.700$

Work Step by Step

1. $log_2(3x+2)-log_4(x)=3 \Longrightarrow \frac{log(3x+2)}{log2}-\frac{log(x)}{log4}=3 \Longrightarrow \frac{log(3x+2)}{log2}-\frac{log(x)}{2log2}=3\Longrightarrow 2log(3x+2)-log(x)=6log2 \Longrightarrow (3x+2)^2=64x \Longrightarrow 9x^2-52x+4=0 \Longrightarrow x=\frac{52\pm\sqrt {52^2-4(9)(4)}}{2(9)}=\frac{26\pm 8\sqrt {10}}{9}\approx0.078,5.700$ 2. Check, $x=\frac{26\pm 8\sqrt {10}}{9}$ fit.
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