Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.6 Logarithmic and Exponential Equations - 4.6 Assess Your Understanding - Page 338: 89

Answer

$-1, \frac{2}{3}$

Work Step by Step

1. $(\sqrt[3] 2)^{2-x}=2^{x^2} \Longrightarrow \frac{2-x}{3}\ ln2=x^2\ ln2 \Longrightarrow 3x^2+x-2=0 \Longrightarrow (3x-2)(x+1)=0 \Longrightarrow x=-1, \frac{2}{3}$ 2. Check, $x=-1, \frac{2}{3}$ fit(s).
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