Answer
$0$
Work Step by Step
1. $\frac{e^x+e^{-x}}{2}=1 \Longrightarrow 2e^x(\frac{e^x+e^{-x}}{2})=2e^x \Longrightarrow e^{2x}-2e^x+1=0 \Longrightarrow e^x=1, x=0$
2. Check, $x=0$ fit(s).
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Section 4.6 Logarithmic and Exponential Equations - 4.6 Assess Your Understanding - Page 338: 91
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