Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.6 Logarithmic and Exponential Equations - 4.6 Assess Your Understanding - Page 337: 56

Answer

$x=\dfrac{3}{\ln{\pi}-1} \approx 20.728$

Work Step by Step

To find the value of $x$, we apply $\log$ to both sides and then isolate $x$ as follows: $$\ln \left(e^{x+3}\right)=\ln \left(\pi^{x}\right)$$ Use the logarithmic properties: $\log m^n= n \log m\quad$ and $\quad \ln{e} = 1$ to obtain: \begin{align*}(x+3)\cdot \ln{e}&=x \cdot \ln\pi \\ (x+3)(1)&=x\cdot \ln{\pi}\\ x+3&=x \cdot \ln\pi\\\ 3&=x\cdot \ln{\pi}-x\\ 3&=x(\ln\pi-1) \\ \dfrac{3}{\ln{\pi}-1}&=x\\ 20.728&\approx x\end{align*} Thus, our answer is: $x =\dfrac{3}{\ln{\pi}-1}\approx 20.728$
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