Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.6 Logarithmic and Exponential Equations - 4.6 Assess Your Understanding - Page 337: 20

Answer

$\frac{15}{4}$

Work Step by Step

1. $log(2x)-log(x-3)=1 \Longrightarrow log(2x)=log(x-3)+log10 \Longrightarrow log(2x)=log(10x-30) \Longrightarrow 2x=10x-30 \Longrightarrow x=\frac{15}{4}$. 2. Check $x=\frac{15}{4}$ fits.
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