Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.6 Logarithmic and Exponential Equations - 4.6 Assess Your Understanding - Page 337: 31

Answer

$x=\dfrac{9}{2}=4.5$

Work Step by Step

Apply the logarithmic property: $\log_a(\dfrac{M}{N}) = \log_a M-\log_a N$ and rearrange the given expression to obtain: $\log_{a}[\dfrac{x-1}{x+6}] =\log_{a}[\dfrac{x-2}{x+3}]$ This gives: $\dfrac{x-1}{x+6}=\dfrac{x-2}{x+3}$ After cross-multiplying the above, we get the following quadratic equation: $x^2+2x-3 =x^2+4x -12$ $2x -9 =0 \implies x =4.5$ Thus, our answer is: $x=\dfrac{9}{2}=4.5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.