Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.4 Logarithmic Functions - 4.4 Assess Your Understanding - Page 322: 98



Work Step by Step

$\because y=\log_a x \text{ is equivalent to } x= a^y$ $\therefore 5x+3 = \log_6 36 \text{ is equivalent to } 36=6^{5x+3}$ With $36=6^2$, solve the equation above using the rule $a^m=a^n\implies m=n$ to obtain: \begin{align*} 36&=6^{5x+3}\\\\ 6^2&=6^{5x+3}\\\\ 2&=5x+3\\\\ 2-3&=5x\\\\ -1&=5x\\\\ \frac{-1}{5}&=\frac{5x}{5}\\\\ -\frac{1}{5}&=x \end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.