Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.4 Logarithmic Functions - 4.4 Assess Your Understanding - Page 322: 110



Work Step by Step

Divide $4$ to both sides of the equation to obtain: $e^{x+1}=\dfrac{5}{4}$ $e^{x+1}=1.25$ $\because e^y=x \text{ is equivalent to } y=\ln{x}$ $\therefore e^{x+1} = 1.25 \text{ is equivalent to } x+1=\ln{1.25}$ Solve the equation above to obtain: \begin{align*} x+1&=\ln{1.25}\\ x&=\ln{1.25}-1\end{align*}
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