## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$\dfrac{\log_{10} {0.375}+7}{2}$
Divide $8$ to both sides of the equation to obtain: $10^{2x-7}=\dfrac{3}{8}$ $10^{2x-7}=0.375$ $\because a^y = x \text{ is equivalent to } \log_a x = y$ $\therefore 10^{2x-7}=0.37\implies \log_{10} 0.375=2x-7$ Solve the equation above to obtain: \begin{align*} 2x-7&=\log_{10} {0.375}\\\\ 2x&=\log_{10} {0.375}+7\\\\ x&=\dfrac{\log_{10} {0.375}+7}{2} \end{align*}