Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.1 Composite Functions - 4.1 Assess Your Understanding - Page 281: 74

Answer

$V(r)=\dfrac{2}{3} \pi r^3$

Work Step by Step

We know that the height is twice the radius, so $h=2r$ The volume is given as: $V=\dfrac{1}{3} \pi r^2 h$ Therefore, the composite function is: $V(r)=\dfrac{1}{3} \pi r^2 h=\dfrac{1}{3} \pi (r^2) (2r)=\dfrac{2}{3} \pi r^3$
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