Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.1 Composite Functions - 4.1 Assess Your Understanding - Page 281: 73


$V(r)=2\pi r^3$

Work Step by Step

We know that the height is twice the radius, so $h=2r$ We know that the volume is given by: $V=\pi r^2 h$ Therefore, the composite function will be: $V(r)=\pi r^2 h=\pi (r^2) (2r)=2\pi r^3$
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