Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.1 Composite Functions - 4.1 Assess Your Understanding - Page 281: 71

Answer

$C(x)=\dfrac{2\sqrt {100-p}}{25}+600$ $; 0\le p \le 100$

Work Step by Step

We will simplify the equation $p=-\dfrac{1}{4}x+100$ in order to isolate the $x$. Thus, we have: $p+\dfrac{1}{4}x=100\\\dfrac{1}{4}x=100-p$ or, $x=400-4p$ Therefore, the composite function will be: $C(x)=\dfrac{\sqrt x}{25}+600 \\ =\dfrac{\sqrt {400-4p}}{25}+600 \\ =\dfrac{2\sqrt {100-p}}{25}+600$ We restrict the $p$ values to be less than $100$ to avoid a negative in the root: Domain: $0\le p \le 100$
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