Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.1 Composite Functions - 4.1 Assess Your Understanding - Page 281: 72

Answer

$C(x)=\dfrac{\sqrt {1000-5p}}{10}+400$; $0\le p\le 200$

Work Step by Step

We will simplify the equation $p=-\dfrac{1}{5}x+200$ in order to isolate the $x$. Thus, we have: $p+\dfrac{1}{5}x=200$ or, $x=1000-5p$ Therefore, the composite function will be: $C(x)=\dfrac{\sqrt x}{10}+400 \\ =\dfrac{\sqrt {1000-5p}}{10}+400$ We restrict $p$ to be less than or equal to $200$ to avoid a negative in the root: Domain: $0\le p\le 200$
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