Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$f^{-1}(x)=(-5,3)$
When finding the inverse of the function, the $x$ and $y$ values get switched. The domain of the function $f(x)$ becomes the range of the inverse function and the range of the inverse function $f^{-1}(x)$ becomes the domain of the function $f(x)$. This means that when $(x,y)$ is on $f$, then $(y,x)$ will be on $f^{-1} (x)$. Therefore, the point on the inverse function is: $f^{-1}(x)=(-5,3)$