Answer
$ 2+3log_2x-log_2(x+3)-log_2(x-6)$
Work Step by Step
$log_2(\frac{4x^3}{x^2-3x-18})=log_2(\frac{4x^3}{(x+3)(x-6)})=log_24+log_2x^3-log_2(x+3)-log_2(x-6)=2+3log_2x-log_2(x+3)-log_2(x-6)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Chapter Test - Page 372: 20
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
