Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Chapter Test - Page 372: 16


$ x=-\ln (2)$

Work Step by Step

We need to simplify $8-2e^{-x} =4$ $-2e^{-x} =-4$ This yields: $e^{-x}=2$ Take $\ln$ on both sides to obtain: $\ln e^{-x}=\ln 2$ Since, $\ln e^{a}=a$ So, $-x =\ln 2$ Therefore, $ x=-\ln (2)$
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