Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Chapter Test - Page 372: 15

Answer

$x=91$ or The solution set is: $\{91\}$

Work Step by Step

The term $125$ can be written as: $125=5^3$ So, the given equation can be equivalent to $5^{x+2}=5^3$ Recall the rule that $\log y =x \longrightarrow 10^x=y$ Applying this rule, we obtain: $\log (x+9) =2 \\ 10^2 =x+9$ Simplify this equation to obtain: $100=x+9 \\ 100-9=x+9-9 \\ x=91$ So, the solution set is: $\{91\}$
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