Answer
$(-\frac{11}{4},\infty)$.
Work Step by Step
Expand the original expression to get $x^2-x-6\lt x^2+3x+5 \Longrightarrow 4x\gt-11 \Longrightarrow x\gt-\frac{11}{4} $ or $(-\frac{11}{4},\infty)$.
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