Answer
$(-\infty,-2]\cup(1,3] $.
Work Step by Step
Step 1. For $\frac{(x-3)(x+2)}{x-1}\le0$, identify boundary points as $x=-2,1,3$.
Step 2. Form intervals $(-\infty,-2],[-2,1),(1,3],[3,\infty)$.
Step 3. Choose test values for each interval $x=-3,0,2,4$.
Step 4. Test the inequality to get results: $True,\ False,\ True,\ False$
Step 5. We have the solution $(-\infty,-2]\cup(1,3] $.
