Chapter 3 - Polynomial and Rational Functions - Section 3.3 Complex Zeros; Fundamental Theorem of Algebra - 3.3 Assess Your Understanding - Page 231: 33

$2,3\pm 2i$ $f(x)=(x-2)(x-3+2i)(x-3-2i)$

Step 1. Use synthetic division (as shown in the figure) to find zero(s) of $f(x)=x^3-8x^2+25x-26$ as $x=2$. Step 2. Use the quotient to find other zeros $x^2-6x+13=0 \Longrightarrow x=\frac{6\pm\sqrt {36-4(13)}}{2}=3\pm 2i$ Step 3. We have $f(x)=(x-2)(x-3+2i)(x-3-2i)$