Answer
$x=\pm1,\pm i$
$f(x)=(x+1)(x-1)(x+i)(x-i)$
Work Step by Step
Step 1. $x^4-1=0 \Longrightarrow (x^2+1)(x+1)(x-1)=0 \Longrightarrow x=\pm1\ and\ x=\pm i$
Step 2. We have $f(x)=(x+1)(x-1)(x+i)(x-i)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 3 - Polynomial and Rational Functions - Section 3.3 Complex Zeros; Fundamental Theorem of Algebra - 3.3 Assess Your Understanding - Page 231: 32
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
