Answer
domain $\{x|x\ne-1\}$.
H.A. $none$, V.A. $x=-1$, O.A. $y=x+1$.
Work Step by Step
Step 1. For $r(x)=\frac{x^2+2x-3}{x+1}=\frac{(x+1)^2-4}{x+1}=x+1-\frac{4}{x+1}$, we can find the domain $\{x|x\ne-1\}$.
Step 2. We can find the horizontal asymptote(s) H.A. $none$, vertical asymptote(s) V.A. $x=-1$, oblique asymptote(s) O.A. $y=x+1$.
