Answer
See below.
Work Step by Step
Step 1. Given $f(x)=-2x^2-3x+8$, we have $f(0)=8\gt0$ and $f(4)=-2(4)^2-3(4)+8=-36\lt0$.
Step 2. Based on the Intermediate Value Theorem, $f(x)$ should have at least one zero on the interval $[0,4]$.
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