Answer
$1,\frac{5\pm\sqrt {61}}{6}$
Work Step by Step
Step 1. For $3x^3+2x-1=8x^2-4\Longrightarrow 3x^3-8x^2+2x+3=0 $, use synthetic division to find zero(s) $x=1$ as shown in the figure.
Step 2. Use the quotient to find other zero(s) $3x^2-5x-3=0\Longrightarrow x=\frac{5\pm\sqrt {25-4(3)(-3)}}{2(3)}=\frac{5\pm\sqrt {61}}{6}$
