Answer
a) $(-\infty, -3 ) \cup (1, \infty)$
b) $[-3,1]$
Work Step by Step
a) We observe from the graph the interval where the function $f$ value is below the value of $g$. We get the interval: $(-\infty, -3 ) \cup (1, \infty)$
(b) We reverse the interval in (a) to get: $[-3,1]$