## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

a) $(-\infty, -3 ) \cup (1, \infty)$ b) $[-3,1]$
a) We observe from the graph the interval where the function $f$ value is below the value of $g$. We get the interval: $(-\infty, -3 ) \cup (1, \infty)$ (b) We reverse the interval in (a) to get: $[-3,1]$