Answer
The solution set is empty (no solutions).
Work Step by Step
We are given:
$25x^2+16 \lt 40 x$
Simplify the given inequality as:
$25x^2+16-40x \lt 0 \\ 25x^2-40 x +16 \lt 0 \\ (5x-4)^2 \lt 0$
We see that $(5x-4)^2 \geq 0$ (the square of all real numbers is non-negative). So the solution set is empty (no solutions).
