## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

a) $x$ is in the interval: $(-\infty,-2) \cup (2, \infty)$. b) $x$ is in the interval $[-2,2]$.
a) We look for the interval where the graph is above the x-axis. We see that this happens before $-2$ and after $2$. Thus, we get: $(-\infty,-2) \cup (2, \infty)$. b) We look for the x-values such that the graph is below or on the x-axis. This is the opposite of (a): the interval $[-2,2]$.