Answer
$\{x|x=-3\}$.
Work Step by Step
Step 1. $x^2+6x+9\le0 \longrightarrow (x+3)^2\le0$.
Step 2. As $(x+3)^2\ge0$, the only solution is $(x+3)^2=0$, thus $\{x|x=-3\}$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Section 2.5 Inequalities Involving Quadratic Functions - 2.5 Assess Your Understanding - Page 163: 13
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