Answer
slope$=1$
See graph.
Work Step by Step
1. Find the derivative of $f(x)=x^3-x^2$ as $f'(x)=3x^2-2x$.
2. The slope of the tangent line is the same as the derivative at $x=1$, we have $m=3(1)^2-2(1)=1$
3. The tangent line is $y-0=(x-1)$ or $y=x-1$
4. See graph.