Answer
slope $=-2$
See graph.
Work Step by Step
1. Find the derivative of $f(x)=3-x^2$ as $f'(x)=-2x$.
2. The slope of the tangent line is the same as the derivative at $x=1$, we have $m=-2(1)=-2$
3. The tangent line is $y-2=-2(x-1)$ or $y=-2x+4$
4. See graph.