Answer
slope$=16$
See graph.
Work Step by Step
1. Find the derivative of $f(x)=-4x^2$ as $f'(x)=-8x$.
2. The slope of the tangent line is the same as the derivative at $x=-2$, we have $m=-8(-2)=16$
3. The tangent line is $y+16=16(x+2)$ or $y=16x+16$
4. See graph.