Answer
$135$
Work Step by Step
We find the limit:
$\lim\limits _{x\to 5} (3x) (x-2)^2 =\lim\limits _{x\to 5} (3x) \times \lim\limits _{x\to 5} (x-2)^2$
or, $=(3)(5) \times (5-2)^2$
or, $=15 \times 9$
or, $=135$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Test - Page 927: 5
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