Answer
$-5$
Work Step by Step
We apply the rule:
$\lim\limits_{x \to a} A(x)=A(a)$
Now find the limit:
$\lim\limits_{x \to 3} (-x^2+3x-5) =[-(3^2)+3(3)-5] \\=-9+9-5 \\=-5$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Test - Page 927: 1
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